查看“打印 err 相关的前后10行”的源代码

=shell=
<pre>
#!/bin/bash
file="your_log_file.log"
# 使用grep找到包含err的行号
line_numbers=$(grep -n "err" $file | cut -d: -f1)
for num in $line_numbers; do
    start=$((num - 10))
    end=$((num + 10))
    if [ $start -lt 1 ]; then
        start=1
    fi
    sed -n "${start},${end}p" $file
    echo "------------------------"
done

</pre>
=py=
<pre>
def print_lines_around_err(file_path):
    with open(file_path, 'r', encoding='utf-8') as file:
        lines = file.readlines()
        for index, line in enumerate(lines):
            if 'err' in line:
                start_index = max(0, index - 10)
                end_index = min(len(lines), index + 11)
                for i in range(start_index, end_index):
                    print(lines[i].strip())
                print("-" * 50)  # 用于分隔不同匹配处的内容

# 使用示例，替换成实际的文件路径
file_path = "your_file.txt"
print_lines_around_err(file_path)

</pre>